2[b-(4b-5)]=3b+5

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Solution for 2[b-(4b-5)]=3b+5 equation:


Simplifying
2[b + -1(4b + -5)] = 3b + 5

Reorder the terms:
2[b + -1(-5 + 4b)] = 3b + 5
2[b + (-5 * -1 + 4b * -1)] = 3b + 5
2[b + (5 + -4b)] = 3b + 5

Reorder the terms:
2[5 + b + -4b] = 3b + 5

Combine like terms: b + -4b = -3b
2[5 + -3b] = 3b + 5
[5 * 2 + -3b * 2] = 3b + 5
[10 + -6b] = 3b + 5

Reorder the terms:
10 + -6b = 5 + 3b

Solving
10 + -6b = 5 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
10 + -6b + -3b = 5 + 3b + -3b

Combine like terms: -6b + -3b = -9b
10 + -9b = 5 + 3b + -3b

Combine like terms: 3b + -3b = 0
10 + -9b = 5 + 0
10 + -9b = 5

Add '-10' to each side of the equation.
10 + -10 + -9b = 5 + -10

Combine like terms: 10 + -10 = 0
0 + -9b = 5 + -10
-9b = 5 + -10

Combine like terms: 5 + -10 = -5
-9b = -5

Divide each side by '-9'.
b = 0.5555555556

Simplifying
b = 0.5555555556

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